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x^2-100x+2.400=0
We add all the numbers together, and all the variables
x^2-100x+2.4=0
a = 1; b = -100; c = +2.4;
Δ = b2-4ac
Δ = -1002-4·1·2.4
Δ = 9990.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-\sqrt{9990.4}}{2*1}=\frac{100-\sqrt{9990.4}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+\sqrt{9990.4}}{2*1}=\frac{100+\sqrt{9990.4}}{2} $
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